3.1548 \(\int \frac{\sqrt{a^2+2 a b x+b^2 x^2}}{d+e x} \, dx\)

Optimal. Leaf size=80 \[ \frac{b x \sqrt{a^2+2 a b x+b^2 x^2}}{e (a+b x)}-\frac{\sqrt{a^2+2 a b x+b^2 x^2} (b d-a e) \log (d+e x)}{e^2 (a+b x)} \]

[Out]

(b*x*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(e*(a + b*x)) - ((b*d - a*e)*Sqrt[a^2 + 2*a*b*x + b^2*x^2]*Log[d + e*x])/(
e^2*(a + b*x))

________________________________________________________________________________________

Rubi [A]  time = 0.0373813, antiderivative size = 80, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.071, Rules used = {646, 43} \[ \frac{b x \sqrt{a^2+2 a b x+b^2 x^2}}{e (a+b x)}-\frac{\sqrt{a^2+2 a b x+b^2 x^2} (b d-a e) \log (d+e x)}{e^2 (a+b x)} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[a^2 + 2*a*b*x + b^2*x^2]/(d + e*x),x]

[Out]

(b*x*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(e*(a + b*x)) - ((b*d - a*e)*Sqrt[a^2 + 2*a*b*x + b^2*x^2]*Log[d + e*x])/(
e^2*(a + b*x))

Rule 646

Int[((d_.) + (e_.)*(x_))^(m_)*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dist[(a + b*x + c*x^2)^Fra
cPart[p]/(c^IntPart[p]*(b/2 + c*x)^(2*FracPart[p])), Int[(d + e*x)^m*(b/2 + c*x)^(2*p), x], x] /; FreeQ[{a, b,
c, d, e, m, p}, x] && EqQ[b^2 - 4*a*c, 0] &&  !IntegerQ[p] && NeQ[2*c*d - b*e, 0]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin{align*} \int \frac{\sqrt{a^2+2 a b x+b^2 x^2}}{d+e x} \, dx &=\frac{\sqrt{a^2+2 a b x+b^2 x^2} \int \frac{a b+b^2 x}{d+e x} \, dx}{a b+b^2 x}\\ &=\frac{\sqrt{a^2+2 a b x+b^2 x^2} \int \left (\frac{b^2}{e}-\frac{b (b d-a e)}{e (d+e x)}\right ) \, dx}{a b+b^2 x}\\ &=\frac{b x \sqrt{a^2+2 a b x+b^2 x^2}}{e (a+b x)}-\frac{(b d-a e) \sqrt{a^2+2 a b x+b^2 x^2} \log (d+e x)}{e^2 (a+b x)}\\ \end{align*}

Mathematica [A]  time = 0.0156397, size = 42, normalized size = 0.52 \[ \frac{\sqrt{(a+b x)^2} ((a e-b d) \log (d+e x)+b e x)}{e^2 (a+b x)} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[a^2 + 2*a*b*x + b^2*x^2]/(d + e*x),x]

[Out]

(Sqrt[(a + b*x)^2]*(b*e*x + (-(b*d) + a*e)*Log[d + e*x]))/(e^2*(a + b*x))

________________________________________________________________________________________

Maple [C]  time = 0.201, size = 44, normalized size = 0.6 \begin{align*}{\frac{{\it csgn} \left ( bx+a \right ) \left ( \ln \left ( bxe+bd \right ) ae-\ln \left ( bxe+bd \right ) bd+bxe+ae \right ) }{{e}^{2}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((b*x+a)^2)^(1/2)/(e*x+d),x)

[Out]

csgn(b*x+a)*(ln(b*e*x+b*d)*a*e-ln(b*e*x+b*d)*b*d+b*x*e+a*e)/e^2

________________________________________________________________________________________

Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((b*x+a)^2)^(1/2)/(e*x+d),x, algorithm="maxima")

[Out]

Exception raised: ValueError

________________________________________________________________________________________

Fricas [A]  time = 1.54714, size = 54, normalized size = 0.68 \begin{align*} \frac{b e x -{\left (b d - a e\right )} \log \left (e x + d\right )}{e^{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((b*x+a)^2)^(1/2)/(e*x+d),x, algorithm="fricas")

[Out]

(b*e*x - (b*d - a*e)*log(e*x + d))/e^2

________________________________________________________________________________________

Sympy [A]  time = 0.585905, size = 20, normalized size = 0.25 \begin{align*} \frac{b x}{e} + \frac{\left (a e - b d\right ) \log{\left (d + e x \right )}}{e^{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((b*x+a)**2)**(1/2)/(e*x+d),x)

[Out]

b*x/e + (a*e - b*d)*log(d + e*x)/e**2

________________________________________________________________________________________

Giac [A]  time = 1.20215, size = 61, normalized size = 0.76 \begin{align*} b x e^{\left (-1\right )} \mathrm{sgn}\left (b x + a\right ) -{\left (b d \mathrm{sgn}\left (b x + a\right ) - a e \mathrm{sgn}\left (b x + a\right )\right )} e^{\left (-2\right )} \log \left ({\left | x e + d \right |}\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((b*x+a)^2)^(1/2)/(e*x+d),x, algorithm="giac")

[Out]

b*x*e^(-1)*sgn(b*x + a) - (b*d*sgn(b*x + a) - a*e*sgn(b*x + a))*e^(-2)*log(abs(x*e + d))